Monday, 4 January 2016

The integral of (4x+3)/(x^2+1) - Version 1



In this video, I demonstrate how to integrate (or find the antiderivative of) the expression...
\int \frac{4x+3}{x^2+1} \mathrm{d}x
by separating the numerator into 2 components. This leads performing two separate, but common integrals of:
\int \frac{4x}{x^2+1} \mathrm{d}x + \int \frac {3}{x^2+1} \mathrm{d}x
The first integral can be performed in the same fashion as shown in the video tutorial on how to integrate 4x/(x^2+6), by using a u-substitution. Watch the video here: https://www.youtube.com/watch?v=c_Wgh6F5d5Y

And the second integral can be performed according to the video tutorial on how to integrate 1/(x2+a2), by using a trigonometric substitution. Watch the video here:  https://www.youtube.com/watch?v=Xi3GdKPK63I 

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