- The powers m and n are both even
- The powers m and n are even and odd respectively
- The powers m and n are odd and even respectively
- The powers m and n are both odd
Remember that cos(x) is the first derivative of sin(x), so we reserve one and write the integrand as...\int \sin^3x\cos^3x\mathrm{d}x
Then if we write the cos2(x) term as...\sin^3x\cos^3x=\sin^3x\cos^2x\cos x
we have...\cos^2x=1-\sin^2x
Then using the substitution u = sin(x), we can easily evaluate the integral.\sin^3x\left [ 1-\sin^2x \right ]\cos x=\left [ \sin^3x-\sin^5x \right ]\cos x
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